Java找到两条线的交点 [英] Java find intersection of two lines
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问题描述
在Java中,我有一个类Line
,它具有两个变量:m
和b
,因此该行遵循公式mx + b
.我有两条这样的台词.如何找到两条线的交点的x
和y
坐标? (假设坡度不同)
In Java, I have a class Line
that has two variables : m
and b
, such that the line follows the formula mx + b
. I have two such lines. How am I to find the x
and y
coordinates of the intersection of the two lines? (Assuming the slopes are different)
这里是class Line
:
import java.awt.Graphics;
import java.awt.Point;
public final class Line {
public final double m, b;
public Line(double m, double b) {
this.m = m;
this.b = b;
}
public Point intersect(Line line) {
double x = (this.b - line.b) / (this.m - line.m);
double y = this.m * x + this.b;
return new Point((int) x, (int) y);
}
public void paint(Graphics g, int startx, int endx, int width, int height) {
startx -= width / 2;
endx -= width / 2;
int starty = this.get(startx);
int endy = this.get(endx);
Point points = Format.format(new Point(startx, starty), width, height);
Point pointe = Format.format(new Point(endx, endy), width, height);
g.drawLine(points.x, points.y, pointe.x, pointe.y);
}
public int get(int x) {
return (int) (this.m * x + this.b);
}
public double get(double x) {
return this.m * x + this.b;
}
}
推荐答案
让我们假设您具有以下两个功能:
Lets assume you have these 2 functions:
y = m1*x + b1
y = m2*x + b2
要找到x-axis
的交点,请执行以下操作:
To find the intersection point of the x-axis
we do:
m1*x+b1 = m2*x+b2
m1*x-m2*x = b2 - b2
x(m1-m2) = (b2-b1)
x = (b2-b1) / (m1-m2)
要查找y,请使用函数表达式,并将x
替换为其值(b2-b1) / (m1-m2)
.
To find y, you use of the function expressions and replace x
for its value (b2-b1) / (m1-m2)
.
所以:
y = m1 * [(b2-b1) / (m1-m2)] + b1
您有(this.b - line.b)
,更改为(line.b - this.b)
.
public Point intersect(Line line) {
double x = (line.b - this.b) / (this.m - line.m);
double y = this.m * x + this.b;
return new Point((int) x, (int) y);
}
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