数学溢出在python中不是很溢出的计算 [英] math overflow for a not very overflowing calculation in python

问题描述

我得到数学溢出数的计算公式是:

The calculation for which I'm getting the math overflow number is:

e2 = math.exp([[-20.7313399283991]])

实际上我完成的极端次数比这更多，为什么这会导致溢出?

There are actually more extreme numbers that I've done than this, why is this causing an overflow?

我收到此错误:

OverflowError: math range error

推荐答案

math.exp()对标量进行运算，而不对矩阵进行运算.

math.exp() operates on scalars, not on matrices.

您可以像这样使用它，而无需使用方括号:

You can use it like so, without the square brackets:

>>> math.exp(-20.7313399283991)
9.919584164742123e-10

如果需要在矩阵上进行运算，则可以使用 numpy.exp() :

If you need to operate on a matrix, you could use numpy.exp():

>>> numpy.exp([[-20.7313399283991]])
array([[  9.91958416e-10]])

这将按元素计算e**x并返回与输入形状相同的数组. (请注意，这与矩阵指数不同；为此，存在 scipy.linalg.expm() .)

This computes the element-by-element e**x and returns an array of the same shape as the input. (Note that this is not the same as the matrix exponential; for that, there is scipy.linalg.expm().)

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