计算字典中值的平均值 [英] working out an average of the values in a dictionary

问题描述

到目前为止，我的字典是这样的:

My dictionary as of now is like this:

class_1 = {'Bob':[9,5,4,3,3,4], 'John':[5,5,7,3,6], 'Andy':[7,5,6,4,5], 'Harris':[3,4,2,3,2,3,2]}

我要使它看起来像这样:

What i am trying to make it look like is this:

class_1_average ={'Bob':[average of scores],'John':[average of scores].........

我该怎么做，以便即使分数更新，平均值也会随之更新.还有一种方法可以从分数中找到最高分数

How can i do this so that even when the scores updates the average also updates with it. And is there also a way to find the highest score out of the scores

推荐答案

尝试如下:

class_1_average = {key: sum(value)/len(value) for key, value in class_1.items()}

对于最大值:您可以对字典的值使用max内置函数

For max value: you can use max built-in function over the value of dictionary

max_each = {key: max(value) for key, value in class_1.items()}

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