发放的允许一个FTP文件的java [英] Giving permission to a ftp FILE java

问题描述

我在android的一类与FTP连接和存储的图像，即可以完美运行的问题是，当我试图将图像移动到另一个目录（我用一个PHP页面来主持的图片）它不有权处理它，我希望把权限为0777，但只有Java的code可以做到这一点，但我不知道怎么了，

我使用FTPClient库

这是我的code

 文件镜像文件=新的文件（URL [0]）;         FTPClient ftpClient =新FTPClient（）; ftpClient.connect（InetAddress.getByName（MYSERVER））;
         ftpClient.login（登录，通行证）;         ftpClient.changeWorkingDirectory（目录）;
         ftpClient.setFileType（FTP.BINARY_FILE_TYPE）;
         的BufferedInputStream buffIn = NULL;
         buffIn =新的BufferedInputStream（新的FileInputStream（镜像文件））;
         ftpClient.enterLocalPassiveMode（）;
         ftpClient.storeFile（URL [1] +，buffInJPG）;
         buffIn.close（）;
         ftpClient.logout（）;
         ftpClient.disconnect（）;
 

解决方案

我被命令做它

  ftpClient.storeFile（URL [1] +，buffInJPG）;
         一个布尔值= ftpClient.sendSiteCommand（文件模式+777+/absolutepath/\"+url[1]+\".jpg）;
 

i have a class in android that connect with the ftp, and store an image, that works perfect the problem is when i am trying to move the image to another directory( i use a php page to moderate that image) it doesnt have permission to handle it, i want to put the permission to 0777 but only the "java code" can do it but i dont know how,

I am using FTPClient library

this is my code

 File imageFile = new File(url[0]); 



         FTPClient ftpClient = new FTPClient();   ftpClient.connect(InetAddress.getByName("myserver"));
         ftpClient.login("login", "pass");

         ftpClient.changeWorkingDirectory("directory");
         ftpClient.setFileType(FTP.BINARY_FILE_TYPE);
         BufferedInputStream buffIn=null;
         buffIn=new BufferedInputStream(new FileInputStream(imageFile));
         ftpClient.enterLocalPassiveMode();
         ftpClient.storeFile(url[1]+".jpg", buffIn);
         buffIn.close();
         ftpClient.logout();
         ftpClient.disconnect();

解决方案

I made it by command

 ftpClient.storeFile(url[1]+".jpg", buffIn);
         boolean a = ftpClient.sendSiteCommand("chmod " + "777 " + "/absolutepath/"+url[1]+".jpg");

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