列出所有成对的n个整数的最快解决方案? [英] Fastest solution to list all pairs of n integers?
问题描述
我想列出所有具有大n
的整数[1, n]
的所有可能对.我发现自己正在寻找最快的选择.到目前为止,这是我想出的.
I want to list all possible pairs of the integers [1, n]
with a large n
. I find myself looking for the fastest option. This is what I've come up with so far.
Matlab的 nchoosek
和
Matlab's nchoosek
and combnk
methods recommend n<15
for listing all possible combinations because of the explosive number of combinations. So how fast this is depends on the n.
pair = nchoosek(1:n, 2);
另一种选择是使用嵌套的for循环
Another option would be to use a nested for loop
kk =1;
pair = zeros(nchoosek(n, 2), 2);
for ii = 1:n
for jj = ii+1:n
pair(kk, :) = [ii, jj];
kk = kk + 1;
end
end
这将相对较慢.
我还考虑过直接使用ind2sub
函数
I also thought of using the ind2sub
function directly
pair_adjacency = tril(ones(n), -1);
[x, y] = ind2sub(size(pair_adjacency), find(pair_adjacency==1));
pair = [x, y];
以循环方式对这些方法进行计时,每次使用n=1000
进行10次,我会变得最快到最慢
Timing these methods in a loop, 10 times each with n=1000
, I get fastest to slowest
- ind2sub(0.15秒)
- for循环(16.3秒)
- nchoosek(16.8秒)
看来ind2sub
是远距离拍摄的最快方法.出于好奇,还有哪些其他选择可能会更快或更可能不会更快?
It seems like ind2sub
is the fastest way to go by a long shot. Just out of curiosity, what are other options that may or may not be faster?
推荐答案
替换nchoosek(1:N,2)
To replace nchoosek(1:N,2)
使用bsxfun
-
[Y,X] = find(bsxfun(@gt,[1:N]',[1:N]))
pair = [X, Y];
仅具有tril
和find
(不具有ind2sub
)-
[y,x] = find(tril(true(N),-1))
pair = [X, Y];
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