用不同的开始/结束元素编号重整行 [英] Reshape row wise w/ different starting/ending elements number

问题描述

问题是:

Product of known dimensions, 3, not divisible into total number of elements, 16.

这是因为我想在3x6矩阵中reshape一个16x1矩阵.问题是起始矩阵有16个元素，而最终矩阵有18个元素.是否存在一种聪明的方法来按行整形并用0填充丢失的元素，直到元素数量匹配为止?

this because i want to reshape a 16x1 matrix in a 3x6 matrix. The problem is that the start matrix has 16 elements and the final matrix has 18. Is there a smart way to reshape row wise and filling the missing element with 0s till the number of elements matches?

当然，我需要一个独立于这些数字的通用方法，因为矩阵的大小可以改变.

Of course I need a general method independent from those number since the size of matrices can change.

TBN:0应当位于矩阵的结尾

TBN: 0s should be at the end of the matrix

推荐答案

方法1

您可以使用 vec2mat 是 Communications System Toolbox 的一部分，假设A作为输入向量-

Approach #1

You can use vec2mat that's part of the Communications System Toolbox, assuming A as the input vector -

ncols = 6; %// number of columns needed in the output
out = vec2mat(A,ncols)

样品运行-

>> A'
ans =
     4     9     8     9     6     1     8     9     7     7     7     4     6     2     7     1
>> out
out =
     4     9     8     9     6     1
     8     9     7     7     7     4
     6     2     7     1     0     0

---

方法2

如果没有该工具箱，则可以使用基本功能来实现相同功能-

---

Approach #2

If you don't have that toolbox, you can work with the basic functions to achieve the same -

out = zeros([ncols ceil(numel(A)/ncols)]);
out(1:numel(A)) = A;
out = out.'

这篇关于用不同的开始/结束元素编号重整行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！