使用mat2cell将MxN矩阵划分为1xN大小的M矩阵 [英] using mat2cell to divide a matrix of MxN into M matrix with 1xN size

问题描述

我有一个MxN大小的矩阵，比方说1867x3、1867行和3列，我想把它变成1867个大小为1x3的单元格. 我使用了mat2cell(X，[1 1866])，这里X是矩阵(1867x3)，结果给出了两个像元，一个像元的大小为1x3，另一个像元为1866x3.我希望所有单元格的大小(1867)为1x3. 我不知道mat2cell是否可以给我想要的结果，还是应该进行循环以使其发生? 谢谢

I have a matrix with the size of MxN, let's say 1867x3, 1867 rows and 3 columns.I I want to make it into 1867 cells with the size of 1x3. I used mat2cell(X,[1 1866]), here X is the matrix (1867x3), the result gave two cells, one cell is the size of 1x3, the other is 1866x3. I want all the cells'(1867) size is 1x3. I don't know if mat2cell could give me the result I want or if I should make a loop so it could happen? Thank you,

推荐答案

尝试一下:

C=mat2cell(X,ones(1,1867),[3]);

该命令基本上说要创建1867个大小为1(行)的单元格，每个单元格包含3个元素.

This command basically says to create 1867 cells of size 1 (in rows) with 3 elements each.

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