将大矩阵拆分为较小的矩阵 [英] Split large matrix to smaller ones

问题描述

我有一个15276x30991矩阵，我想将其拆分为3个较小的矩阵，我知道我必须使用mat2cell函数，但是我无法正确设置尺寸.你能帮我实现这个目标吗?

I have a 15276x30991 matrix and I would like to split it to 3 smaller matrices i know that I have to use mat2cell function but I cannot manage to set the dimensions correctly. Could you please help me on how can i achieve this?

示例对于要分解为30x25维的矩阵300x25的矩阵300x25，应为

Example For a matrix 300x25 to split in to 10 matrices of 30x25 dimensions should be

Mcell = mat2cell(A,repmat(30,10,1),25)

推荐答案

要将行中的矩阵分成三个矩阵，请尝试:

To split the matrix along the rows into three matrices, try:

>> x = rand(15276,100);
>> C = mat2cell(x, ones(3,1)*(size(x,1)/3), size(x,2))
C = 
    [5092x100 double]
    [5092x100 double]
    [5092x100 double]

这假设size(x,1)被3整除，在您的情况下，这是正确的:15276/3 = 5092

This assumes that size(x,1) is evenly divisible by 3, which is true in your case: 15276/3 = 5092

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