在Python中用较小的矩阵制作较大的矩阵 [英] Making bigger matrices out of smaller matrices in Python

问题描述

我在用较小的矩阵制作较大的矩阵时遇到问题.

I have a problem making a bigger matrix out of smaller matrixs.

假设我有矩阵:

      1 2 3
  A=  4 5 6
      7 8 9

和

      1 0 0 
  B=  0 1 0
      0 0 1

我想要得到的结果是

    1 2 3 1 0 0
C = 4 5 6 0 1 0
    7 8 9 0 0 1

如果我要在MATLab中进行此操作，就像做C = [A B]一样简单

If I'm to do this in MATLab it would be as simple as doing C = [A B]

但是我现在正在使用python.

But I'm working with python at the momment.

一个人怎么能在python中做那件事?

How could one do that thing in python?

顺便说一句，在python中，矩阵A和B将由我的程序生成，它们将是ndarrays(在我的问题上，它们是15000x1626数组或矩阵，如果需要的话).

Btw, in python the matrices A and B would be made by my program and they would be ndarrays (at my problem, they are 15000x1626 arrays, or matrices, if needed to be).

非常感谢您的帮助.

推荐答案

尝试使用 np.hstack :

C = np.hstack((A,B))

或 np.concanenate :

C = np.concatenate((A,B),axis=1)

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