如何用行和除矩阵元素 [英] how to divide matrix elements by sum of row

问题描述

我想将矩阵的每个元素除以该元素所属的行的总和.例如:

I want to divide each element of a matrix by the sum of the row that element belongs to. For example:

[1 2      [1/3 2/3 
 3 4] ==>  3/7 4/7]

我该怎么办?谢谢.

推荐答案

A = [1 2; 3 4]

A =[1 2; 3 4]

diag(1./sum(A，2))* A

diag(1./sum(A,2))*A

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