如何匹配除空格和新行之外的任何内容? [英] How to matches anything except space and new line?

问题描述

我有一个字符串，我只想匹配除空格和新行之外的任何字符的字符串.什么必须是正则表达式?

I have a string, I just want to match string for any character except for space and new line. What must be regular expression for this?

我知道除空格以外的任何正则表达式，即 [^ ]+ 和除新行 [^\n]+ 以外的任何正则表达式(我在 Windows 上)).我不知道如何将他们聚集在一起.

I know regular expressions for anything but space i.e. [^ ]+ and regular expression for anything but new line [^\n]+ (I'm on Windows). I am not able to figure how to club them together.

推荐答案

您可以将空格字符添加到要排除的字符类中.

You can add the space character to your character class to be excluded.

^[^\n ]*$

正则表达式

^              # the beginning of the string
 [^\n ]*       # any character except: '\n' (newline), ' ' (0 or more times)
$              # before an optional \n, and the end of the string

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