正则表达式，除所有空格外，均与其他任何内容匹配 [英] Regex that matches anything except for all whitespace

问题描述

我需要一个(与javascript兼容的)正则表达式，它将匹配除仅包含空格的字符串以外的任何字符串.案例:

I need a (javascript compliant) regex that will match any string except a string that contains only whitespace. Cases:

" "         (one space) => doesn't match
"    "      (multiple adjacent spaces) => doesn't match
"foo"       (no whitespace) => matches
"foo bar"   (whitespace between non-whitespace) => matches
"foo  "     (trailing whitespace) => matches
"  foo"     (leading whitespace) => matches
"  foo   "  (leading and trailing whitespace) => matches

推荐答案

这将查找至少一个非空白字符.

This looks for at least one non whitespace character.

/\S/.test("   ");      // false
/\S/.test(" ");        // false
/\S/.test("");         // false


/\S/.test("foo");      // true
/\S/.test("foo bar");  // true
/\S/.test("foo  ");    // true
/\S/.test("  foo");    // true
/\S/.test("  foo   "); // true

---

我想我假设一个空字符串应该只考虑空格.

---

I guess I'm assuming that an empty string should be consider whitespace only.

如果一个空字符串(技术上它不包含所有空格，因为它不包含任何空格)应该通过测试，则将其更改为...

If an empty string (which technically doesn't contain all whitespace, because it contains nothing) should pass the test, then change it to...

/\S|^$/.test("  ");      // false

/\S|^$/.test("");        // true
/\S|^$/.test("  foo  "); // true

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