在圆上绘制角度线并获取相交点 [英] Draw angles lines over circle and get the intersecting points

问题描述

我希望在圆上绘制角度线(我在脚本中更改角度).我得到的绘图线是0角，为什么脚本没有向我显示所有角度，我该如何解决? 另外，如何计算相交点?

I wish to draw angle lines over a circle (I change the angles in the script). The plot line I get is 0 angle, why does the script not show me all of them, and how can I fix it? In addition, how can I calculate the intersection points?

脚本:

clc;
clear;
close all;

r=1000;

% based on : https://stackoverflow.com/questions/29194004/how-to-plot-a-circle-in-matlab
nCircle = 1000;

t = linspace(0,2*pi,nCircle);

xCircle = 0+ r*sin(t);  
yCircle = 0+ r*cos(t);  

line(xCircle,yCircle );

axis equal;
hold on;

nAngles = 45;
inceasedNumber = 360/nAngles;
lineLength = r+50;

for angle = 0:359:inceasedNumber
    xLine(1) = 0;
    yLine(1) = 0;
    xLine(2) = xLine(1) + lineLength * cosd(angle);
    yLine(2) = yLine(1) + lineLength * sind(angle);
    plot(xLine, yLine);
end

推荐答案

我认为您的for循环的定义有误.步长必须出现在迭代的开始和结束之间的中间位置:

I think there is a mistake in the definition of your for loop. The stepsize must appear in the middle between start and end of the iteration:

for angle = 0:inceasedNumber:359

此外，MATLAB使用弧度指定角度，因此360°等于2pi，您必须相应地更改输入.

Furthermore MATLAB is using Radians to specify an angle, hence 360° equals 2pi and you have to change your inputs accordingly.

对于直线和圆的交点，在实现之前我会考虑几何形状；)

For the intersection of the lines and the circle I would consider geometry before implementation ;)

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