如何从幅值和相位信息创建复数表示以执行快速傅里叶逆变换(IFFT)? [英] How to create the complex representation from magnitude and phase information to perform an inverse fast fourier transform(IFFT)?

问题描述

我在将幅度和相位数据转换为复数形式时遇到问题，这是执行IFFT所必需的. (快速傅立叶逆变换).这是我仅有的数据.

我的频率范围从0.1到2.6，有200个样本.我想使用IFFT来获取时间信号.如何将这个幅值和相位数据集转换为复杂平面?

我以前从未使用过IFFT(或fft)，所以一些有用的见解将非常有帮助！

解决方案

假设您想要这样的复杂表示形式:

a = 3+4i; 
magnitude = abs(a);
phase = angle(a);

您应该将幅度= 5，并且theta = 0.9273

现在要求逆并获取复杂的表示形式，请使用公式:

 z = magnitude*exp(i*phase)

如果一切正常，则应该恢复复杂的表示形式.

I have a problem with converting amplitude and phase data into the complex form, which is required to perform an IFFT. (inverse fast fourier transform). This is the only data I have.

My frequency range goes from 0.1 to 2.6 and, with 200 samples. I would like to use IFFT to obtain a time signal. How do I convert this magnitude and phase dataset into the complex plane?

I have never used IFFT (Or fft) before, so some helpful insights would be very helpful!

解决方案

Assuming you want the complex representation like this:

a = 3+4i; 
magnitude = abs(a);
phase = angle(a);

you should have magnitude = 5, and theta = 0.9273

Now to inverse and obtain back your complex representation, use the formula:

 z = magnitude*exp(i*phase)

if all goes correctly, you should have the complex representation back.

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