单元阵列的排名 [英] Ranking of a cell array

问题描述

以下面的示例为例:

clear all
Name1 = {'Data1','Data2','Data3','Data4'};
Data = {6.2,6,3.2,8};
CombnsName = nchoosek(Name1,2);
CombnsData = nchoosek(Data,2);

for i = 1:length(CombnsData);
    multiplied{i} = CombnsData{i,1}.*CombnsData{i,2};
end
multiplied = multiplied';
Final = [CombnsName, multiplied];
Rankd = sort(cell2mat(multiplied));

在此，Final表示通过将"Name1"的每种可能组合相乘而获得的值.现在，我试图找到一种方法来更改最终"的顺序以与"Rankd"定义的排名顺序相对应.例如，Final的第一行应为"Data2'Data3'19.2；最后一个行"应显示为"Data1"，"Data4" 49.6.

Here, Final represents the values gained by multiplying every possible combination of 'Name1'. Now, I'm trying to find a way of changing the order of 'Final' to correspond to the ranking order defined by 'Rankd'. For example the first 'line' of Final should read 'Data2 'Data3' 19.2; and the last 'line' should read 'Data1' Data4' 49.6.

有没有这样做的方法?

推荐答案

有两个选项.首先，您可以使用sort的第二个输出，它为您提供与已排序数组中的条目相对应的索引:

There are a couple of options. Firstly, you could use the second output of sort, which gives you the indexes corresponding to the entries in the sorted array:

>> [Rankd Index] = sort(cell2mat(multiplied));

然后做

>> Final(Index,:)

ans = 

    'Data2'    'Data3'    [19.200000000000003]
    'Data1'    'Data3'    [19.840000000000003]
    'Data3'    'Data4'    [25.600000000000001]
    'Data1'    'Data2'    [37.200000000000003]
    'Data2'    'Data4'    [                48]
    'Data1'    'Data4'    [49.600000000000001]

但是，更简单的方法是使用专门针对这种情况设计的功能sortrows:

However, an even easier method is to use the function sortrows which was designed for exactly this situation:

>> sortrows(Final,3)

ans = 

    'Data2'    'Data3'    [19.200000000000003]
    'Data1'    'Data3'    [19.840000000000003]
    'Data3'    'Data4'    [25.600000000000001]
    'Data1'    'Data2'    [37.200000000000003]
    'Data2'    'Data4'    [                48]
    'Data1'    'Data4'    [49.600000000000001]

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