在向量Matlab中检查单元格的邻居 [英] check the neighbours of a cell in a vector Matlab

问题描述

我有两个向量

K=[1 1 1 2 1 2 1 4 2 10 4 5 1] 

和

L=[2 0 1 2 1 2 1 3 2 0 1 2 1]

我想将每个向量中的第7个元素的值与该值的邻居进行比较，其中邻居是在每一侧与该元素相邻的5个元素.因此，对于K，第7个元素是1，邻居是1 1 1 2 1 2(左邻居)和4 2 10 4 5 1(右邻居).

I want to compare the value of the 7th element in each vector with the neighbours of this value, where the neighbours are 5 elements next to this element in each side. So for K, the 7th element is 1 and the neighbours are 1 1 1 2 1 2 (left neighbours) and 4 2 10 4 5 1 (right neighbours).

对于L，第7个元素是1，邻居是2 0 1 2 1 2(左邻居)和3 2 0 1 2 1(右邻居).如果第7个值与它的每个邻居之间的差值大于某个阈值，那么我将做某事，例如X = 1，如果不是，那么我将做另一件事，例如X=2.

For L, the 7th element is 1 and the neighbours are 2 0 1 2 1 2 (left neighbours) and 3 2 0 1 2 1 (right neighbours). If the difference between the 7th value and each of its neighbours is above a certain threshold then I'll do something e.g X=1, if not then I'll do another thing e.g X=2.

因此在我的示例中，我将阈值设置为3，因此对于K，第7个元素值是1，并且它与它的两个相邻元素10,5之间的差大于阈值3，所以X将是1 .对于L，第5个元素的值为1，并且它与所有相邻元素之间的差小于阈值3，因此X为2.不知道是否可以不使用循环来节省时间.

So in my example I'll set the threshold to 3, so for K the 7th element value is 1 and the difference between it and two of its neighbours 10,5 are more than the threshold value 3 so X will be 1. For L the 5th element value is 1 and the difference between it and all of its neighbours is less than the threshold value 3 so X will be 2. So I'm wondering if anyone could assist me to do this condition, I'm not sure if this can be done without loops to save time.

推荐答案

您可以使用any和or来检查这种情况:

You can check this condition using any and or:

N = 5; % reference index
T = 3; % threshold

V = L; % used to pass the vector L to the if-statement
% V = K;

% formulate if-statement to check for values
% below/above index N and check if any difference
% exceeds the threshold
% the or-statement (because it does not matter if the 
% threshold is exceeded above index N or below)
% is expressed as |

if any((V(1:N-1)-V(N))>T) | any((V(N+1:end)-V(N))>T)
    X = 1;
else
    X = 2;
end

注意
取决于您的Matlab版本，V(1:N-1)-V(N)将不起作用，因为矩阵尺寸不一致.在这种情况下，请使用:V(1:N-1)-ones(size(V(1:N-1))).*V(N)

Note
Depending on your Matlab version V(1:N-1)-V(N) will not work, because the matrix dimensions do not agree. In this case use: V(1:N-1)-ones(size(V(1:N-1))).*V(N)

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