如何根据表格扫描每个单词的值，然后计算出来，然后从中制作VSM(向量空间模型) [英] How to scan values from each words based on tables and then calculate it And Make The VSM (Vector Space Model) From It

问题描述

说我有一个表，其中包含另一个表中每个单词的概率.该表有2个类别. actual 和 non_actual .我将其命名为 master_table

Say that I have a table that contains probabilities from each words from another table. This Table has 2 classes; actual and non_actual. I will name it master_table

 actual = [0.5;0.4;0.6;0.75;0.23;0.96;0.532]; %sum of the probabilities is 1.     
actual + non_actual = 1
non_actual = [0.5;0.6:0.4;0.25;0.77;0.04;0.468];
words = {'finn';'jake';'iceking';'marceline';'shelby';'bmo';'naptr'};
master_table = table(actual,non_actual,...
'RowNames',words)

然后我有一个包含句子的表格.我将其命名为T2

And then I have a table that contains sentences. I will name it T2

sentence = {'finn marceline naptr';'jake finn simon marceline haha';'jake finn finn jake iceking';'bmo shelby shelby finn naptr';'naptr naptr jake finn bmo shelby'}
T2 = table('RowNames',sentence)

如何制作(不属于master_table的单词，例如"simon"，"haha​​"具有值1，因此不会影响确定该类的概率的计算):

How to make like this (Words that dont belong in the master_table like "simon", "haha" have value 1, so it wont affects the calculation of the probabilities to determine the class) :

                                    actual %determines the value based on probabilities from each words%        non_actual               class
finn marceline naptr                0.5 * 0.75 * 0.532                                                         0.5 * 0.25 * 0.468        compares the value from each class. if actual > non_actual then the class should be "actual"
jake finn simon marceline haha      0.4 * 0.5 * 1 * 0.25 * 1                                                   0.6 * 0.5 * 1 * 0.75 * 1
jake finn finn jake iceking
bmo shelby shelby finn naptr
naptr naptr jake finn bmo shelby

以及如何根据上述问题制作VSM(向量空间模型):

And how to make the VSM (vector space model) from the problem above:

                                                                        WORDS                                   
                                    | bmo | finn | jake | iceking | haha | marceline | naptr | shelby | simon |     %words sorted alphabetically      
finn marceline naptr                   0     1       0        0       0        1         1       0       0      
jake finn simon marceline haha         0     1       1        0       1        1         0       0       1
jake finn finn jake iceking            0     2       2        1       0        0         0       0       0
bmo shelby shelby finn naptr           1     1       0        0       0        0         1       1       0      
naptr naptr jake finn bmo shelby       1     1       1        0       0        0         1       1       0       

推荐答案

这也有点循环，但是我觉得性能不是问题.我会先创建一个更大的表，然后在循环中更改值:

This is a bit loopy as well but i fell like performance is not an issue. I would create a bigger table first and then change the values in a loop:

T2 = table(ones(height(T2),1),ones(height(T2),1),repmat({''},height(T2),1),'RowNames',sentence,'VariableNames',{'actual' 'non_actual' 'outcome'});

for i=1:height(T2)
    % split the row name
    A=strsplit([T2.Properties.RowNames{i,:}]);
    actual=1; %which is neutral for multiplication
    non_actual=1; 
    for j=1:length(A)
       actual = actual *  master_table{A(j),1};
       non_actual = non_actual *  master_table{A(j),2};
    end
    %if you need those
    T2.actual(i)=actual;
    T2.non_actual(i)=non_actual;

    if actual > non_actual
        T2.outcome(i)={'actual'};
    else
        T2.outcome(i)={'non_actual'};
    end;
end;

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