seaborn color_palette作为matplotlib颜色图 [英] seaborn color_palette as matplotlib colormap

问题描述

Seaborn提供了一个称为color_palette的功能，该功能使您可以轻松地为绘图创建新的color_palettes.

Seaborn offers a function called color_palette, which allows you to easily create new color_palettes for plots.

colors = ["#67E568","#257F27","#08420D","#FFF000","#FFB62B","#E56124","#E53E30","#7F2353","#F911FF","#9F8CA6"]

color_palette = sns.color_palette(colors)

我想将color_palette转换为cmap，可以在matplotlib中使用它，但是我不知道如何做到这一点.

I want to transform color_palette to a cmap, which I can use in matplotlib, but I don't see how I can do this.

可悲的是，像"cubehelix_palette"，"light_palette"之类的函数具有"as_cmap"参数.不幸的是，"color_palette"没有.

Sadly just functions like "cubehelix_palette","light_palette",… have an "as_cmap" paramater. "color_palette" doesn't, unfortunately.

推荐答案

您必须将颜色列表从海洋调色板转换为matplolib的颜色映射(建议更改为@RafaelLopes):

You have to convert a list of colors from seaborn palette to color map of matplolib (thx to @RafaelLopes for proposed changes):

import seaborn as sns
import matplotlib.pylab as plt
import numpy as np
from matplotlib.colors import ListedColormap

# construct cmap
flatui = ["#9b59b6", "#3498db", "#95a5a6", "#e74c3c", "#34495e", "#2ecc71"]
my_cmap = ListedColormap(sns.color_palette(flatui).as_hex())

N = 500
data1 = np.random.randn(N)
data2 = np.random.randn(N)
colors = np.linspace(0,1,N)
plt.scatter(data1, data2, c=colors, cmap=my_cmap)
plt.colorbar()
plt.show()

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