在保留网格的同时删除x轴刻度线(matplotlib) [英] Remove the x-axis ticks while keeping the grids (matplotlib)

问题描述

我想删除x轴上的刻度线，但保持垂直网格.当我执行以下操作时，我同时失去了x轴刻度和网格.

I want to remove the ticks on the x-axis but keep the vertical girds. When I do the following I lose both x-axis ticks as well as the grid.

import matplotlib.pyplot as plt
fig = plt.figure() 
figr = fig.add_subplot(211)
...
figr.axes.get_xaxis().set_visible(False)
figr.xaxsis.grid(True)

在使x轴刻度线不可见的同时如何保留网格?

How can I retain the grid while makeing x-axis ticks invisible?

推荐答案

通过删除刻度线，您是说删除刻度线标签还是刻度线本身?这将删除标签:

By remove the ticks, do you mean remove the tick labels or the ticks themselves? This will remove the labels:

import matplotlib.pyplot as plt
import numpy as np

x = np.linspace(0, 2*np.pi, 100)

fig = plt.figure()
ax = fig.add_subplot(111)

ax.plot(x, np.sin(x))

ax.grid(True)
ax.set_xticklabels([])


plt.show()

---

如果您真的想摆脱那些小的刻度线，可以添加以下内容:

---

If you really want to get rid of the little tick lines, you can add this:

for tic in ax.xaxis.get_major_ticks():
    tic.tick1On = tic.tick2On = False

您可以关闭对勾标签 a>此处也无需通过设置tic.label1On = tic.label2On = False来求助于ax.set_xticklabels([])"hack":

You could turn the tick labels off here too without resorting to the ax.set_xticklabels([]) "hack" by setting tic.label1On = tic.label2On = False:

import matplotlib.pyplot as plt
import numpy as np

x = np.linspace(0, 2*np.pi, 100)

fig = plt.figure()
ax = fig.add_subplot(111)

ax.plot(x, np.sin(x))

ax.grid(True)
for tic in ax.xaxis.get_major_ticks():
    tic.tick1On = tic.tick2On = False
    tic.label1On = tic.label2On = False

plt.show()

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