删除matplotlib中子图上的重叠刻度线 [英] remove overlapping tick marks on subplot in matplotlib

问题描述

我使用以下函数创建了以下子图集:

I've create the following set of subplots using the following function:

def create31fig(size,xlabel,ylabel,title=None):
    fig = plt.figure(figsize=(size,size))
    ax1 = fig.add_subplot(311)
    ax2 = fig.add_subplot(312)
    ax3 = fig.add_subplot(313)
    plt.subplots_adjust(hspace=0.001)
    plt.subplots_adjust(wspace=0.001)
    ax1.set_xticklabels([])
    ax2.set_xticklabels([])
    xticklabels = ax1.get_xticklabels()+ ax2.get_xticklabels()
    plt.setp(xticklabels, visible=False)
    ax1.set_title(title)
    ax2.set_ylabel(ylabel)
    ax3.set_xlabel(xlabel)
    return ax1,ax2,ax3

如何确保子图(312)的顶部和底部与相邻区域不重叠?谢谢.

How do I make sure the top and bottom of subplot(312) do not overlap with their neighbours? Thanks.

推荐答案

在置顶模块中有一个名为

In the ticker module there is a class called MaxNLocator that can take a prune kwarg.
Using that you can remove the topmost tick of the 2nd and 3rd subplots:

import matplotlib.pyplot as plt
from matplotlib.ticker import MaxNLocator # added 

def create31fig(size,xlabel,ylabel,title=None):
    fig = plt.figure(figsize=(size,size))
    ax1 = fig.add_subplot(311)
    ax2 = fig.add_subplot(312)
    ax3 = fig.add_subplot(313)
    plt.subplots_adjust(hspace=0.001)
    plt.subplots_adjust(wspace=0.001)
    ax1.set_xticklabels([])
    ax2.set_xticklabels([])
    xticklabels = ax1.get_xticklabels() + ax2.get_xticklabels()
    plt.setp(xticklabels, visible=False)
    ax1.set_title(title)
    nbins = len(ax1.get_xticklabels()) # added 
    ax2.yaxis.set_major_locator(MaxNLocator(nbins=nbins, prune='upper')) # added 
    ax2.set_ylabel(ylabel)
    ax3.yaxis.set_major_locator(MaxNLocator(nbins=nbins,prune='upper')) # added 
    ax3.set_xlabel(xlabel)
    return ax1,ax2,ax3

create31fig(5,'xlabel','ylabel',title='test')

在进行这些调整后对图像进行采样:

Sample image after making those adjustments:

另外:如果最低子图中重叠的 x 和 y 标签是一个问题，请考虑修剪"其中之一.

Aside: If the overlapping x- and y- labels in the lowest subplot are an issue consider "pruning" one of those as well.

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