如何根据所述的JSONObject响应显示吐司 [英] How to show toast according to the JSONObject response

问题描述

我做在我使用的用户名和密码，日志应用程序中，如果登录成功后我越来越USER_ID所有，但无效用户试图登录，必须出示敬酒消息给用户。我越来越 {错误：invalid_grant} 作为我JSONresponse和我能够在一个字符串得到的JSONObject

 的JSONObject jObject =新的JSONObject（结果）;
字符串aJsonString = jObject.getString（错误）;
 

下面aJsonString有错误的价值在里面。

现在，我的问题是：
如何当非法用户试图登录显示错误信息？而且，如果用户是有效通行证用户采取进一步行动 postExecute（）方法。

解决方案

 的JSONObject jObject;    尝试{
        jObject =新的JSONObject（的sampleData）;
        如果（jObject.has（错误））{
字符串aJsonString = jObject.getString（错误）;
Toast.makeText（ActivityName.this，aJsonString，Toast.LENGTH_LONG）.show（）;
        }其他{
    Toast.makeText（ActivityName.this登录成功，Toast.LENGTH_LONG）.show（）;
        }
    }赶上（JSONException E1）{
        // TODO自动生成catch块
        e1.printStackTrace（）;
    }
 

I am doing an application in which I'm using username and password for log in, if log in is successful I'm getting user_id and all, but when invalid user try to log in, will have to show toast message to the user. I'm getting {"error":"invalid_grant"} as my JSONresponse and I'm able to get JSONObject in a string.

JSONObject jObject = new JSONObject(result);
String aJsonString = jObject.getString("error");

Here aJsonString have the value of error in it.

Now, my question is: How to show an error message when invalid user tries to log in? And, if the user is valid pass the user to postExecute() method for further action.

解决方案

JSONObject jObject;

    try {
        jObject = new JSONObject(sampledata);
        if (jObject.has("error")) {
String aJsonString = jObject.getString("error");
Toast.makeText(ActivityName.this, aJsonString, Toast.LENGTH_LONG).show();
        } else {
    Toast.makeText(ActivityName.this, "Login Successful", Toast.LENGTH_LONG).show();
        }
    } catch (JSONException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

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