来自响应的 okhttp 新 JsonObject [英] okhttp new JsonObject from Response
本文介绍了来自响应的 okhttp 新 JsonObject的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用 OKHttp
和 https://github.com/hongyangAndroid/okhttp-utils
来实现登录功能,但我不知道如何在回调中创建新的 JsonObject
使用响应.
I am trying to use OKHttp
and https://github.com/hongyangAndroid/okhttp-utils
to implement Login function, but I don't know how to create new a JsonObject
use Response in the Callback.
OkHttpUtils.post()
.url(url)
.addParams("phone", "18681873411")
.addParams("password", "18681873411")
.build()
.execute(new Callback() {
@Override
public Object parseNetworkResponse(Response response) throws Exception {
Log.i("ws","---->>parseNetworkResponse" + response.body().string());
JSONObject jsonObj = null;
try {
jsonObj = new JSONObject(response.body().string());
} catch (JSONException e) {
Log.i("ws","---->>JSONException");
e.printStackTrace();
} catch (IOException e) {
Log.i("ws","---->>IOException");
e.printStackTrace();
}
Log.i("ws","---->>111 :" );
String opCode = jsonObj.getString("OpCode");
String message = jsonObj.getString("Message");
Log.i("ws","---->>111 opCode:" + opCode);
Log.i("ws","---->>111 Message:" + message);
JSONObject result = new JSONObject();
result.put("qrcode",opCode);
result.put("message", message);
return result;
}
@Override
public void onError(Call call, Exception e) {
Log.i("ws","---->>onError" + e);
}
@Override
public void onResponse(Object response) {
Log.i("ws","---->>onResponse" + response.toString());
}
});
和错误信息:
parseNetworkResponse{"OpCode":0,"Message":"登陆成功","Other":{"id":1,"name":null,"phone":"18681873411","QQuid":null,"weixinuid":null,"gender":null,"age":null,"credits":null,"address":null,"signature":null,"imageurl":null,"password":"18681873411","created_at":"2016-05-19T17:05:02.000Z","updated_at":"2016-05-19T17:05:02.000Z"}}
05-20 11:29:01.953 13496-13621/com.smartspace.magicmirror I/ws: ---->>IOException
05-20 11:29:01.954 13496-13621/com.smartspace.magicmirror I/ws: ---->>111 :
05-20 11:29:01.955 13496-13496/com.smartspace.magicmirror I/ws: ---->>onErrorjava.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.getString(java.lang.String)' on a null object reference
推荐答案
由于调用 response.body().string()
会从返回流中读取内容然后关闭它,所以第二次调用它.它不会返回任何内容:\
Since the call response.body().string()
will read the content from the return stream then close it, so the second time you call it. It will return nothing :\
更好的方法:
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
String responseData = response.body().string();
Log.e(TAG, "onResponse: " + responseData);
try {
JSONObject jsonObject = new JSONObject(responseData);
// Do something here
} catch (JSONException e) {
...}
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