如何打包资源，以便可以从其他Maven工件中访问它们? [英] How to package resources so that they can be accessed from other Maven artifacts?
问题描述
我正在编写一个系统，该系统将包含
I'm writing a system, which will consist of
- 专有的，封闭源代码的核心组件和
- 几个插件，我打算与它们的源一起分发.
目前，这些只是Maven项目，例如myapp-core(专有)和myapp-plugin1(与源代码一起分发).
For now, these are simply Maven projects, let's say myapp-core (proprietary) and myapp-plugin1 (distributed with the source code).
myapp-plugin1通过以下方式使用myapp-core. myapp-plugin1中有一个主类:
myapp-plugin1 uses myapp-core in the following way. There is a main class in myapp-plugin1:
public class DisplayHouseholdsOnMapApp {
public static void main(final String[] aArgs) {
CoreApp app = new CoreApp();
try {
app.run(new MenuBarFactory(), new GlassPaneDisplay());
} catch (final IOException | ClassNotFoundException | SQLException exception) {
exception.printStackTrace();
}
}
}
CoreApp在myapp-core项目中定义，其他所有内容(MenuBarFactory，GlassPaneDisplay)-在myapp-plugin1项目中定义.
CoreApp is defined in the myapp-core project, everything else (MenuBarFactory, GlassPaneDisplay) - in the myapp-plugin1 project.
在CoreApp.run内部，发生了几件事.除其他外，它尝试从存储在myapp-core/src/main/resources文件夹中的文件中加载数据.
Inside CoreApp.run several things happen. Among other things, it tries to load data from files stored in myapp-core/src/main/resources folder.
启动myapp-plugin1时出现错误-myapp-core中定义的类无法加载该文件夹中定义的文件.
When I launch myapp-plugin1, I get errors - classes defined in myapp-core cannot load files defined in that folder.
现在我使用类似的构造读取这些数据
Now I read these data using constructs like
import com.google.common.io.Files;
final List<String> lines = Files.readLines(aFile, Charsets.UTF_8);
当我在myapp-plugin1中使用该项目时，如何在myapp-core中读取这些文件，以使其起作用?
How can I read these files in myapp-core so that it works, when I use that project in myapp-plugin1 ?
更新1:堆栈跟踪.
java.io.FileNotFoundException: src\main\resources\XXXX.csv (Das System kann den angegebenen Pfad nicht finden)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:131)
at com.google.common.io.Files$FileByteSource.openStream(Files.java:127)
at com.google.common.io.Files$FileByteSource.openStream(Files.java:117)
at com.google.common.io.ByteSource$AsCharSource.openStream(ByteSource.java:404)
at com.google.common.io.CharSource.getInput(CharSource.java:87)
at com.google.common.io.CharSource.getInput(CharSource.java:63)
at com.google.common.io.CharStreams.readLines(CharStreams.java:325)
at com.google.common.io.Files.readLines(Files.java:747)
at com.google.common.io.Files.readLines(Files.java:718)
18:19:29.896 [AWT-EventQueue-0] ERROR r.a.c.p.impl.gui.PrimCityGlassPane -
java.io.FileNotFoundException: src\main\resources\XXX.csv (Das System kann die angegebene Datei nicht finden)
at java.io.FileInputStream.open(Native Method) ~[na:1.8.0-ea]
at java.io.FileInputStream.<init>(FileInputStream.java:131) ~[na:1.8.0-ea]
at com.google.common.io.Files$FileByteSource.openStream(Files.java:127) ~[guava-15.0.jar:na]
at com.google.common.io.Files$FileByteSource.openStream(Files.java:117) ~[guava-15.0.jar:na]
at com.google.common.io.ByteSource$AsCharSource.openStream(ByteSource.java:404) ~[guava-15.0.jar:na]
at com.google.common.io.CharSource.getInput(CharSource.java:87) ~[guava-15.0.jar:na]
at com.google.common.io.CharSource.getInput(CharSource.java:63) ~[guava-15.0.jar:na]
at com.google.common.io.CharStreams.readLines(CharStreams.java:325) ~[guava-15.0.jar:na]
at com.google.common.io.Files.readLines(Files.java:747) ~[guava-15.0.jar:na]
at com.google.common.io.Files.readLines(Files.java:718) ~[guava-15.0.jar:na]
更新2:
我尝试使用以下代码读取数据.
I tried to read the data using following code.
import com.google.common.io.Resources;
import com.google.common.base.Charsets;
final URL resource = getClass().getClassLoader().getResource(aFile.getPath().substring
("src\\main\\resources\\".length()));
final List<String> lines = Resources.readLines(resource, Charsets.UTF_8);
但是现在，当我运行myapp-plugin1时，出现以下异常.
But now, when I run myapp-plugin1 I get following exception.
Exception in thread "main" java.lang.NullPointerException
at com.google.common.base.Preconditions.checkNotNull(Preconditions.java:192)
at com.google.common.io.Resources$UrlByteSource.<init>(Resources.java:79)
at com.google.common.io.Resources$UrlByteSource.<init>(Resources.java:74)
at com.google.common.io.Resources.asByteSource(Resources.java:68)
at com.google.common.io.Resources.asCharSource(Resources.java:113)
at com.google.common.io.Resources.newReaderSupplier(Resources.java:104)
at com.google.common.io.Resources.readLines(Resources.java:154)
at com.google.common.io.Resources.readLines(Resources.java:176)
推荐答案
当然，您可以在具有依赖项的另一个工件中使用一个工件，但是您需要资源. 因此，在这里，您可以使用maven-dependency-plugin来实现以下目标:解包，请在需要时分阶段解压.您可以放置在outputDirectory = target/classs中的所有未打包人员 这是一个使用maven-dependency-plugin解压缩两个工件的示例:
Sure you can use one artifact in an other with a dependency but you ask for resources. So here how you can do, use the maven-dependency-plugin with the goal: unpack, take care you unpack in a phase befor you need them. All the unpacked staff you can place in outputDirectory=target/classes Here an example with unpacking of two artifacts with the maven-dependency-plugin:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<executions>
<execution>
<id>unpack</id>
<phase>generate-resources</phase>
<goals>
<goal>unpack</goal>
</goals>
<configuration>
<artifactItems>
<artifactItem>
<groupId>org...</groupId>
<artifactId>...</artifactId>
<version>...</version>
<type>jar</type>
<overWrite>true</overWrite>
<outputDirectory>target/classes</outputDirectory>
<includes>**/*.class,**/*.xml</includes>
</artifactItem>
<artifactItem>
<groupId>...</groupId>
<artifactId>...</artifactId>
<version>...</version>
<type>jar</type>
<overWrite>true</overWrite>
<outputDirectory>target/classes</outputDirectory>
<includes>**/*.class</includes>
</artifactItem>
</artifactItems>
</configuration>
</execution>
</executions>
</plugin>
这篇关于如何打包资源，以便可以从其他Maven工件中访问它们?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
