如何访问maven项目中的XML文件，以便在打包时保持可用 [英] How to access a XML file in a maven project so it stays available when packaged

问题描述

我目前正在开发一个maven web-app项目，需要使用jetty启动：在eclipse中进行开发/调试的运行爆炸目标。

I currently started working on a maven web-app project that needs to be launched with the jetty:run-exploded goal for development/debugging in eclipse.

现在，我有一个XML文件，我需要在运行时访问这些内容。我的问题是：在哪里放置文件，以便执行读取的代码在爆炸和打包（即在WAR）模式下工作？

Now, I have an XML file which contents I need to access at runtime. My problem is: where to put the file so that the code that does the reading works both in "exploded" and packaged (i.e. in the WAR) mode?

放置src / main / java中的文件（以便在类路径中）不会删除它，因为maven过滤掉包装上的所有非java文件。
当文件在src / main / resources中时，一个意思是找出项目的根路径（在eclipse开发期间）并查看该目录 - 但是当这个目录不再是这种情况时项目将被打包。

Putting the file in src/main/java (so as to be in the classpath) won't cut it since maven filters out all non-java files on packaging. When the file is in src/main/resources, one mean would be to figure out the root path of the project (during eclipse development) and look into that directory - but this won't be the case anymore when the project will be packaged.

当然，我可以编写试图从两个位置读取文件的代码，但这看起来相当麻烦。有什么建议？

Of course I could go into writing code that tries to read the file from both locations, but this seems rather cumbersome. Any suggestions?

推荐答案

复制 src / main / resources 中的文件到目标/类目录，并在类路径上可用。只需从类路径中读取它们即可。如如何向我的JAR添加资源？中所述maven文档（这里有一个测试资源）：

Files in src/main/resources are copied to the target/classes directory and are available on the class path. Just read them from the class path. As explained in How do I add resources to my JAR? from the maven documentation (with a test resource here):

在单元测试中，你可以使用一个简单的
代码片段，如以下
访问
测试所需的资源：

In a unit test you could use a simple snippet of code like the following to access the resource required for testing:

...

// Retrieve resource
InputStream is = getClass().getResourceAsStream("/test.properties" );

// Do something with the resource

...

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