最大和最小算法? (目标C) [英] Algorithm for max and min? (Objective-C)
问题描述
这是我正在阅读以学习Objective-C的书的一部分.
This is a part of a book I'm reading to learn Objective-C.
下面定义了一个名为MAX的宏,该宏最多提供两个 值:
#define MAX(a,b) ( ((a) > (b)) ? (a) : (b) )
The following defines a macro called MAX that gives the maximum of two values:
#define MAX(a,b) ( ((a) > (b)) ? (a) : (b) )
然后在书中进行一些练习,要求读者定义一个宏(MIN
)以查找两个值中的最小值,另一个要求定义一个名为MAX3
的宏,该宏最多提供3个值价值观.我认为这两个定义看起来与MAX
类似,但我不理解MAX
公式如何找到最大值.我的意思是如果我这样做
And then there are some exercises in the book that asks the reader to define a macro (MIN
) to find the minimum of two values and another that asks to define a macro called MAX3
that gives the maximum of 3 values. I think these two definitions will look similar to MAX
, but I don't understand how the MAX
formula finds the maximum value. I mean if I just did this
int limits = MAX (4,8)
它将仅将limits
的值分配为8.这与查找变量的最大值有什么关系?
It'll just assign limits
the value of 8. What does that have to do with finding a variable's maximum value?
推荐答案
我认为您在混淆值和变量.您列出的宏示例扩展为两个值之间的比较,并返回两个值中较大的一个(即,较大的a
或b
).没错,int limits = MAX(4,8)
只是将8
分配给limits
,与查找可以存储在limits
中的最大值无关.
I think you are confusing value and variable. The macro example you listed expands to a comparison between two values and returns the greater of the two values (i.e. which is greater, a
or b
). So you are right, int limits = MAX(4,8)
just assigns 8
to limits
and has nothing to do with finding the maximum value you can store in limits
.
标头limits.h定义了许多值,例如INT_MAX
,它们将告诉您有关系统上变量类型的最小/最大值的信息.
The header limits.h defines many values like INT_MAX
that will tell you information about the min/max values of variable types on your system.
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