需要对最大和最小构建函数的解释 [英] need explanation for max and min building function

问题描述

我不明白python 2.7中的内置函数max和min

I don't understand the built-in functions max and min in python 2.7

max("sehir")
min("sehir")

max 给出字母 "s" 和 min 给出字母 "e"

max gives the letter "s" and min gives the letter "e"

推荐答案

max 和 min 作为参数(假设你只给它一个unnamedem> 参数)一个 iterable，并返回最大/最小项.

max and min take as parameter (given you only give it one unnamed parameter) an iterable, and returns the maximum / minimum item.

一个字符串是一个可迭代的:如果你对一个字符串进行迭代，你会得到作为字符串字符的 1-char 字符串.

A string is an iterable: if you iterate over a string, you obtain the 1-char strings that are the characters of the string.

然后 max 和 min 迭代那个可迭代对象并返回 maximum 或 minimum 项.对于字符串，定义了字典顺序.所以 'a' <'b' 和 'ab' >'aa'.所以是按字典序比较，个别字符比较是ASCII码(Unicode码="post-tag" title="显示问题标记为 'python-3.x'" rel="tag">python-3.x).由于所有字符都是单字符字符串.这里我们只需要考虑ASCII 码.您可以在此处查看 ASCII 表 [wiki].

Then max and min iterate over that iterable and returns the maximum or minimum item. For a string the lexicographical order is defined. So 'a' < 'b', and 'ab' > 'aa'. So it is compared lexicographically, and the individual characters are compared by ASCII code (Unicode code in python-3.x). Since all characters have are one-caracter strings. We only have to take the ASCII code into account here. You can inspect the ASCII table here [wiki].

所以 max("sehir") 将返回 's'，因为 max(['s', 'e', 'h', 'i', 'r']) == 's':迭代中的最大字符.对于 min('sehir') == 'e'，由于 min(['s', 'e', 'h', 'i', 'r']) =='e' 因为它是字符串中的最小"字符.

So max("sehir") will return 's', since max(['s', 'e', 'h', 'i', 'r']) == 's': the maximum character in the iterable. For min('sehir') == 'e', since min(['s', 'e', 'h', 'i', 'r']) == 'e' because it is the "smallest" character in the string.

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