从用户那里获取电话号码打印最大和最小(不使用内置功能) [英] get numbers from user & print maximum and minimum (w/o using built-in function)

问题描述

我正在审查一个执行以下操作的python练习:

I'm reviewing a python exercise which does the following :

• 读取直到完成"的数字列表 输入.

• reads list of numbers til "done" gets entered.

输入完成"时，打印 最大和最小 数字.

When "done" is inputted, print largest and smallest of the numbers.

并且应该为，而不能直接 使用内置函数max() 和min().

And it should be without directly using the built-in functions, max() and min().

这是我的消息来源. Traceback说:'float'对象不可迭代"

Here is my source. Traceback says, "'float' object is not iterable"

我认为我的错误是由于未正确使用列表来计算最小和最大. 任何提示和帮助将不胜感激！

I think my errors are coming from not using the list properly to calculate smallest and largest. Any tips and help will be greatly appreciated!

while True:
    inp = raw_input('Enter a number: ')
    if inp == 'done' : 
        break

    try:
        num = float(inp)
    except:
        print 'Invalid input'
        continue                            

numbers = list(num)
minimum = None       
maximum = None

for num in numbers :                          
    if minimum == None or num < minimum :
        minimum = num

for num in numbers :        
    if maximum == None or maximum < num :
        maximum = num

print 'Maximum:', maximum
print 'Minimum:', minimum

谢谢！

推荐答案

您不需要列表.您只需要随时跟踪当前的最小值和最大值.

You shouldn't need a list. You should only need to keep track of the current minimum and maximum as you go.

minimum = None
maximum = None

while True:
    inp = raw_input('Enter a number: ')
    if inp == 'done': 
        break

    try:
        num = float(inp)
    except:
        print 'Invalid input'
        continue                            

    if minimum is None or num < minimum:
        minimum = num

    if maximum is None or num > maximum:
        maximum = num

print 'Maximum:', maximum
print 'Minimum:', minimum

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