从contactlist的Andr​​oid获取电话号码 [英] Android Get phone number from contactlist

问题描述

下面，code拿到电话号码，从contactlist retrive电话号码。它的工作原理来回回名。但我不能让PHONENUMBER请给我code得到提前电话number.Thanks ........

  CR = getContentResolver（）;
    contactList = cr.query（ContactsContract.Contacts.CONTENT_URI，NULL，NULL，NULL，NULL）;
    如果（contactList.getCount（）大于0）
    {而（contactList.moveToNext（））
    {ID = contactList.getString（contactList getColumnIndex（ContactsContract.Contacts._ID））;
    名称= contactList.getString（contactList getColumnIndex（ContactsContract.Contacts.DISPLAY_NAME））;
    数= contactList.getString（contactList。
getColumnIndex（ContactsContract.CommonDataKinds.Phone.NUMBER））;
        cntctArrayList.add（数）;
    Log.e（，姓名）;
    的System.out.println（CONTACT_ID：+身份证+联系人姓名：+号码）;}
}
 

解决方案

试试这个：

  ContentResolver的CR = getContentResolver（）;
   光标CUR = cr.query（ContactsContract.Contacts.CONTENT_URI，空，
                NULL，NULL，NULL）;  如果（cur.getCount（）大于0）{
  而（cur.moveToNext（））{
  字符串ID = cur.getString（cur.getColumnIndex（ContactsContract.Contacts._ID））;
  字符串名称= cur.getString（cur.getColumnIndex（ContactsContract.Contacts.DISPLAY_NAME））;
如果（的Integer.parseInt（cur.getString（cur.getColumnIndex（ContactsContract.Contacts.HAS_PHONE_NUMBER）））大于0）{ 光标pCur = cr.query（ContactsContract.CommonDataKinds.Phone.CONTENT_URI，
        空值，
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID
            +=？，新的String [] {ID}，
       空值）; 而（pCur.moveToNext（））{
  串PHONENO = pCur.getString（pCur.getColumnIndex（ContactsContract.CommonDataKinds.Phone.NUMBER））;
    }                }
            }
  }
 

Here ,code to get phone number to retrive phone number from contactlist . it works fro "name" . but i can not get phonenumber please give me code to get phone number.Thanks in Advance........

    cr = getContentResolver(); 
    contactList = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null,   null,null);      
    if(contactList.getCount() > 0)
    {while(contactList.moveToNext())
    {id = contactList.getString(contactList.             getColumnIndex(ContactsContract.Contacts._ID));
    name = contactList.getString(contactList.         getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
    number = contactList.getString(contactList.
getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
        cntctArrayList.add(number);             
    Log.e("", name);
    System.out.println("Contact_id:"+id+"Contact name:"+number);}
}

解决方案

Try this:

   ContentResolver cr = getContentResolver();
   Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                null, null, null);

  if (cur.getCount() > 0) {
  while (cur.moveToNext()) {
  String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
  String name =   cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {  

 Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
        null,
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID
            + " = ?", new String[] { id },
       null);



 while (pCur.moveToNext()) {
  String phoneNo =   pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
    }

                }
            }
  }

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