进不去的Andr​​oid 2.3.3电话号码 [英] Could not get phone number in Android 2.3.3

问题描述

我写了一个简单的应用程序取得联系的电话号码。然而，在电话号码返回空。

下面是我的code：

 私人无效queryContactPhoneNumber（）{
    // TODO自动生成方法存根
    的String [] COLS =新的String [] {People.NAME，People.NUMBER};
    乌里myContacts = People.CONTENT_URI;
    光标mqCur = managedQuery（myContacts，COLS，NULL，NULL，NULL）;
    如果（mqCur.moveToFirst（））
    {
        字符串MYNAME = NULL;
        字符串为mynumber = NULL;
        做
        {
            MYNAME = mqCur.getString（mqCur.getColumnIndex（People.NAME））;
            为mynumber = mqCur.getString（mqCur.getColumnIndex（People.NUMBER））;
            Toast.makeText（这一点，MYNAME ++为mynumber，Toast.LENGTH_SHORT）.show（）;
        }
        而（mqCur.moveToNext（））;
    }
}
 

解决方案

试试这个，

 乌里myContacts = ContactsContract.CommonDataKinds.Phone.CONTENT_URI; // People.CONTENT_URI;
        光标mqCur = managedQuery（myContacts，NULL，NULL，NULL，NULL）;
        如果（mqCur.moveToFirst（））
        {
            字符串MYNAME = NULL;
            字符串为mynumber = NULL;
            做
            {
                MYNAME = mqCur.getString（mqCur.getColumnIndexOrThrow（ContactsContract.Contacts.DISPLAY_NAME））;
                为mynumber = mqCur.getString（mqCur
                        .getColumnIndexOrThrow（ContactsContract.CommonDataKinds.Phone.NUMBER））;
                Toast.makeText（这一点，MYNAME ++为mynumber，Toast.LENGTH_SHORT）.show（）;
            }
            而（mqCur.moveToNext（））;
        }
 

我想这会帮助你。

I write a simple application to get phone number in Contacts. However, the phone number return "null".

Here is my code:

private void queryContactPhoneNumber() {
    // TODO Auto-generated method stub
    String[] cols = new String[] {People.NAME, People.NUMBER};
    Uri myContacts = People.CONTENT_URI;
    Cursor mqCur =  managedQuery(myContacts, cols, null, null, null);
    if(mqCur.moveToFirst())
    {
        String myname = null;
        String mynumber = null;
        do
        {
            myname = mqCur.getString(mqCur.getColumnIndex(People.NAME));
            mynumber = mqCur.getString(mqCur.getColumnIndex(People.NUMBER));
            Toast.makeText(this, myname + " " + mynumber, Toast.LENGTH_SHORT).show();
        }
        while(mqCur.moveToNext());
    }
}

解决方案

Try this,

Uri myContacts = ContactsContract.CommonDataKinds.Phone.CONTENT_URI ;//People.CONTENT_URI;
        Cursor mqCur =  managedQuery(myContacts, null, null, null, null);
        if(mqCur.moveToFirst())
        {
            String myname = null;
            String mynumber = null;
            do
            {
                myname = mqCur.getString(mqCur.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
                mynumber = mqCur.getString(mqCur
                        .getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
                Toast.makeText(this, myname + " " + mynumber, Toast.LENGTH_SHORT).show();
            }
            while(mqCur.moveToNext());
        }

I think this will help you.

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