R中的按元素均值 [英] Element-wise mean in R

问题描述

在R中，我有两个向量:

In R, I have two vectors:

a <- c(1, 2, 3, 4)
b <- c(NA, 6, 7, 8)

如何找到两个向量的逐元素均值，不带循环地删除NA?即我想获得

How do I find the element-wise mean of the two vectors, removing NA, without a loop? i.e. I want to get the vector of

(1, 4, 5, 6)

我知道函数mean()，我知道参数na.rm = 1.但是我不知道如何把东西放在一起.可以肯定的是，实际上我有成千上万个带有NA的向量出现在不同的位置，因此任何依赖于维度的解决方案都行不通.谢谢.

I know the function mean(), I know the argument na.rm = 1. But I don't know how to put things together. To be sure, in reality I have thousands of vectors with NA appearing at various places, so any dimension-dependent solution wouldn't work. Thanks.

推荐答案

操作方法:

rowMeans(cbind(a, b), na.rm=TRUE)

或

colMeans(rbind(a, b), na.rm=TRUE)

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