在Android的正是创建此字符串 [英] Create this string exactly in Android

问题描述

我要建立2相同的产品，为Android和iOS。
iOS的已经工作，但Android的犯规，这是因为该字符串的格式。

在IOS是这样的：

 的NSString * jsonString = [[NSString的页头] initWithFormat：@{\\ID \\：\\％@ \\，\\经度\\：\\％@ \\ ，\\纬\\：\\％@ \\，\\时间戳\\：\\％@ \\}，_phonenumber，经度，纬度，stringFromDate]
 

，我不知道如何在Android的做到这一点exactely这样。这里的格式是不同的。
我现在拥有的是：

 的HttpClient HttpClient的=新DefaultHttpClient（）;
        HttpPost httppost =新HttpPost（http://www.myserver.nl/locatie.php）;        尝试{
            //添加数据
            清单＆LT;＆的NameValuePair GT; namevaluepairs中=新的ArrayList＆LT;＆的NameValuePair GT;（4）;           nameValuePairs.add（新BasicNameValuePair（ID，NUM））;
           nameValuePairs.add（新BasicNameValuePair（经度，茇））;
           nameValuePairs.add（新BasicNameValuePair（纬度，LAT））;
           nameValuePairs.add（新BasicNameValuePair（时间戳，时间））;
           httppost.setEntity（新UrlEn codedFormEntity（namevaluepairs中））;
           HTT presponse响应= httpclient.execute（httppost）;        }赶上（ClientProtocolException E）{        }赶上（IOException异常五）{        }
 

在此先感谢，我需要这在本周结束，所以如果你能帮助我，那将是极大的AP preciated

我得到这个作为一个结果，从IOS字符串：

  

{ID：0612833398，东经： - 143.406417，纬度：32.785834，时间戳：10-10 07:56}

好吧，这是我的问题是什么。

是的，我需要这个确切字符串发送到一个asp.net文件的服务器上。但我需要知道如何将此与此相结合：用HTTP POST到

  HttpPost httppost =新HttpPost（http://www.myserver.nl/locatie.php）;
 

在我这个组合，像这样的nameValuePPairs

  

httppost.setEntity（新UrlEn codedFormEntity（namevaluepairs中））;

解决方案

创建你在IOS通过创建一个JosnObject为获得相同的字符串：

  JSONObject的JSON =新的JSONObject（）;
json.put（ID，0612833398）;
json.put（经度，-143.406417）;
json.put（纬度，32.785834）;
json.put（时间戳，10-10 07:56）;
 

现在，如果你为JSON对象的打印你会得到这个字符串：

  {ID：0612833398，东经： -  143.406417，纬度：32.785834
                                                   时间戳：10-10 07:56}
 

和邮政的JSONObject作为服务器：

  {尝试
        HttpClient的HttpClient的=新DefaultHttpClient（）;        HttpPost httppost =新HttpPost（http://www.myserver.nl/locatie.php）;
        httppost.setHeader（内容类型，应用/ JSON）;//这里创建JSON对象...
    JSONObject的JSON =新的JSONObject（）;
    json.put（ID，0612833398）;
    json.put（经度，-143.406417）;
    json.put（纬度，32.785834）;
    json.put（时间戳，10-10 07:56）;///创建StringEntity当前JSON obejct    StringEntity本身=新StringEntity（json.toString（））;
    se.setContentEncoding（新BasicHeader（HTTP.CONTENT_TYPE，应用/ JSON））;
    httppost.setEntity（SE）;        HTT presponse响应= httpclient.execute（httppost）;
        字符串TEMP = EntityUtils.toString（response.getEntity（））;    }赶上（ClientProtocolException E）{  }
 

I want to build 2 same products for Android and iOs. The iOs already works, but the android doesnt, that's because of the format of the string.

in iOs this is:

NSString*jsonString = [[NSString alloc] initWithFormat:@"{\"id\":\"%@\",\"longitude\":\"%@\",\"latitude\":\"%@\",\"timestamp\":\"%@\"}", _phonenumber, longitude , latitude, stringFromDate];

And i dont know how to do this exactely like this in android. The format here is different. What i have now is:

HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://www.myserver.nl/locatie.php");

        try {
            // Add your data
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);

           nameValuePairs.add(new BasicNameValuePair("id", num));
           nameValuePairs.add(new BasicNameValuePair("longitude", longi));
           nameValuePairs.add(new BasicNameValuePair("latitude", lat));
           nameValuePairs.add(new BasicNameValuePair("timestamp", time));
           httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
           HttpResponse response = httpclient.execute(httppost);

        } catch (ClientProtocolException e) {

        } catch (IOException e) {

        } 

Thanks in advance, i need this by the end of the week so if you could help me, that would be greatly appreciated

i get this as an result from the iOs string:

{"id":"0612833398","longitude":"-143.406417","latitude":"32.785834","timestamp":"10-10 07:56"}

Okay, this is what my problem is.

Yes i need to send this exact string to an asp.net file on a server. But i need to know how to combine this with this: with the http post to

          HttpPost httppost = new HttpPost("http://www.myserver.nl/locatie.php");

before i combined this with the nameValuePPairs like this

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

解决方案

Create same string as you are getting in IOS by create an JosnObject as:

JSONObject json = new JSONObject(); 
json.put("id", "0612833398"); 
json.put("longitude", "-143.406417"); 
json.put("latitude", "32.785834"); 
json.put("timestamp", "10-10 07:56"); 

now if you make a print for json object you will get this string :

{"id":"0612833398","longitude":"-143.406417","latitude":"32.785834",
                                                   "timestamp":"10-10 07:56"}

and Post JSONObject as to server :

  try {
        HttpClient httpclient = new DefaultHttpClient();

        HttpPost httppost = new HttpPost("http://www.myserver.nl/locatie.php");
        httppost.setHeader("Content-type", "application/json");

// Create json object here...
    JSONObject json = new JSONObject(); 
    json.put("id", "0612833398"); 
    json.put("longitude", "-143.406417"); 
    json.put("latitude", "32.785834"); 
    json.put("timestamp", "10-10 07:56"); 

/// create StringEntity with current json obejct

    StringEntity se = new StringEntity(json.toString()); 
    se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
    httppost.setEntity(se); 

        HttpResponse response = httpclient.execute(httppost);
        String temp = EntityUtils.toString(response.getEntity());

    } catch (ClientProtocolException e) {

  } 

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