如何获得大于最大整数值的整数值 [英] How to get an integer value that is greater than the maximum integer value

问题描述

我知道在Java中，一个int可以得到2,147,483,647的值.但是我想要更多的价值.我有一个公式，例如:

I know that in Java an int can get a value of 2,147,483,647. But I want more value than that. I have a formula for example:

double x = a/(b*c); 

因此分母(b * c)可以达到10 ^ 10甚至更​​高.但是无论何时执行公式，该值始终限制为2,147,483,647.我知道，因为x必须始终小于1.0. P/S:如果满足某些条件，即使变量"a"也可以达到10 ^ 10. a，b，c都是整数.

So the denominator (b*c) can reach to 10^10 or maybe even higher than that. But whenever I execute the formula, the value is always limited to 2,147,483,647. I know because x must always be smaller than 1.0. P/S: Even variable "a" can also reach 10^10 if some conditions are satisfied. a,b,c are all integer numbers.

推荐答案

自从您提出要求以来，这是一个BigInteger示例:

Since you asked for it, here's a BigInteger example:

BigInteger a = new BigInteger("yourNumberInStringFormA");
BigInteger b = new BigInteger("yourNumberInStringFormB");
BigInteger c = new BigInteger("yourNumberInStringFormC");

BigInteger x = a.divide(b.multiply(c));

其中"yourNumberInStringForm"是可选的负号和仅数字(没有空格或逗号).例如，BigInteger z = new BigIntger("-3463634");注意:如果您的电话号码在其范围内，BigInteger实际上将为您返回一个long. longs以L结尾，如下所示:

Where "yourNumberInStringForm" is an optional minus sign and numbers only (no whitespace or commas). For example BigInteger z = new BigIntger("-3463634"); NB: BigInteger will actually return a long for you if your number is in its range. longs end in L, as in:

long num = 372036854775807L;

long的最大长度为:9,223,372,036,854,775,807.如果您的数字将小于此数字，那么使用long或Long作为其包装器，而不是BigInteger，将使您的生活变得更加轻松.由于使用long，您不必使用除法/乘法等方法.

The max length for a long is: 9,223,372,036,854,775,807. If your numbers are going to be less than that, it'll make your life a ton easier to use long or Long, its wrapper, over BigInteger. Since with long, you don't have to use methods for dividing/multiplying, etc.

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