Mercurial的"hg clone"，却忽略了所有子仓库? [英] Mercurial `hg clone` but ignoring all subrepos?

问题描述

是否有一种方法可以克隆subrepos附带的存储库，而无需Mercurial提取所有subrepos?

Is there a way to clone a repo that comes with subrepos, but without having Mercurial pull all the subrepos?

看来，虽然hg clone -U可用于获取存储库的空克隆，但没有什么能说服hg update避免通过拉出所有子存储库而开始.

It appears that while hg clone -U can be used to obtain an empty clone of a repo, there's nothing that would convince hg update to avoid starting off by pulling all of the subrepos.

我应该指出，创建这样的克隆后，保持轻松同步至头部修订版本的能力至关重要.

I should point out that it is crucial to retain the ability to easily sync to the head revision after creating such a clone.

推荐答案

此答案可能超出了所需的范围，但在无法更新错误的子存储库路径或修订版本时，提供了一些有关使用Mercurial的宝贵说明.

This answer may add more than the question required, but provides some valuable notes on working with Mercurial when you can't update do to a bad subrepository path or revision.

第1步:克隆存储库而不进行任何更新

Step 1: Clone the repository without any updates

hg clone --noupdate source_repository destination_repository

第2步:使用还原获取正确的文件

Step 2: Use revert to get the right files

hg revert --all --rev revision_number --exclude subrepo_1 --exclude subrepo_2 ...

这时，您有了一个新的变更集；您可能需要确保上级修订是正确的.当我这样做时，我的新变更集的父级是变更集0.要解决此问题，我必须设置父级变更集并切换分支(因为我的变更集位于另一个分支上).

At this point, you have a new changeset; you may need to make sure the parent revision is correct. When I did this, my new changeset's parent was changeset 0. To fix this I had to set the parent changeset AND switch branches (since my changeset was on a different branch).

第3步:更改当前更改的上级

Step 3: Change the parent of the current changes

hg debugsetparents revision_number
hg branch branch_name

应该这样做.

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