Python:断言变量是实例方法吗? [英] Python : Assert that variable is instance method?

问题描述

如何检查变量是否是实例方法?我正在使用python 2.5.

How can one check if a variable is an instance method or not? I'm using python 2.5.

类似这样的东西:

class Test:
    def method(self):
        pass

assert is_instance_method(Test().method)

推荐答案

是您想确定是否确实有一种方法，而不仅仅是可以调用的方法.

inspect.ismethod is what you want to find out if you definitely have a method, rather than just something you can call.

import inspect

def foo(): pass

class Test(object):
    def method(self): pass

print inspect.ismethod(foo) # False
print inspect.ismethod(Test) # False
print inspect.ismethod(Test.method) # True
print inspect.ismethod(Test().method) # True

print callable(foo) # True
print callable(Test) # True
print callable(Test.method) # True
print callable(Test().method) # True

如果参数是方法，函数(包括lambda)，具有__call__的实例或类，则

callable为true.

callable is true if the argument if the argument is a method, a function (including lambdas), an instance with __call__ or a class.

方法具有与函数不同的属性(例如im_class和im_self).所以你想要

Methods have different properties than functions (like im_class and im_self). So you want

assert inspect.ismethod(Test().method)  

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