Python:断言该变量是实例方法? [英] Python : Assert that variable is instance method?

问题描述

如何检查变量是否是实例方法?我使用的是 python 2.5.

How can one check if a variable is an instance method or not? I'm using python 2.5.

像这样:

class Test:
    def method(self):
        pass

assert is_instance_method(Test().method)

推荐答案

inspect.ismmethod 是你想知道你是否确实有一个方法，而不仅仅是你可以调用的东西.

inspect.ismethod is what you want to find out if you definitely have a method, rather than just something you can call.

import inspect

def foo(): pass

class Test(object):
    def method(self): pass

print inspect.ismethod(foo) # False
print inspect.ismethod(Test) # False
print inspect.ismethod(Test.method) # True
print inspect.ismethod(Test().method) # True

print callable(foo) # True
print callable(Test) # True
print callable(Test.method) # True
print callable(Test().method) # True

如果参数是方法、函数(包括 lambdas)、带有 __call__ 的实例，则

callable 为真，或者一类.

callable is true if the argument if the argument is a method, a function (including lambdas), an instance with __call__ or a class.

方法具有与函数不同的属性(例如 im_class 和 im_self).所以你想要

Methods have different properties than functions (like im_class and im_self). So you want

assert inspect.ismethod(Test().method)  

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