如何在MIPS中访问单词的各个位的状态? [英] How do I access the state of individual bits of a word in MIPS?

问题描述

我正在编写程序，我需要确定是否设置了第3位和第6位.我知道我可以旋转一个单词或向左/向右移动它.

I'm writing a program and I need to determine if bits 3 and 6 are set. I know that I can rotate a word or left/right shift it.

但是如何访问单个位的状态?我是否使用像and/xor之类的按位运算符?

But how do I access individual bit's state? Do I use a bitwise operator like and/xor?

推荐答案

您将按位进行操作，并使用0x08和0x40(假定位0是最低位).您将使用andi指令执行此操作.

You would do a bitwise and with 0x08 and 0x40 (presuming bit 0 is the lowest order bit). You would use the andi instruction to do this.

如果$ t0是您要测试的值:

If $t0 is the value you want to test:

andi $t1, $t0, 0x08
andi $t2, $t0, 0x40

如果设置了第3位，$ t1将为非零，如果设置了第6位，则$ t2将为非零.

$t1 will be non-zero if bit 3 is set, $t2 will be non-zero if bit 6 is set.

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