什么创造大量接触的最快的方法？ [英] Whats the fastest way to create large numbers of contacts?

问题描述

在我的应用程序需要创建联系人的大量。

In my application i need to create a great amount of contacts.

在code我currenly使用：

The code I currenly use:

        ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
        ops.add(ContentProviderOperation.newInsert(ContactsContract.RawContacts.CONTENT_URI)
                .withValue(ContactsContract.RawContacts.ACCOUNT_TYPE, accounts[0].type)
                .withValue(ContactsContract.RawContacts.ACCOUNT_NAME, accounts[0].name)
                .build());
        ops.add(ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0)
                .withValue(ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE)
                        .withValue(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME, name)
                        .build());
        ops.add(ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0)
                .withValue(ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
                        .withValue(ContactsContract.CommonDataKinds.Phone.NUMBER, number)
                        .withValue(ContactsContract.CommonDataKinds.Phone.TYPE, ContactsContract.CommonDataKinds.Phone.TYPE_HOME)
                        .build());
        ops.add(ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0)
                .withValue(ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
                        .withValue(ContactsContract.CommonDataKinds.Phone.NUMBER, number)
                        .withValue(ContactsContract.CommonDataKinds.Phone.TYPE, ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE)
                        .build());


        try {
            cr.applyBatch(ContactsContract.AUTHORITY, ops);
        } catch (RemoteException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (OperationApplicationException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

有关接触的一些数量的code运行完美，但如果我创造大量那么这个code workt放缓。因此，我的问题：请告诉我以最快的方式联系人创建大量

For some amounts of contacts the code works perfect, but if I create large amount then this code workt to slow. Therefore my question: Whats the fastest way to create large numbers of contacts?

在此先感谢，观念的任何建议都欢迎。

Thanks in advance, any suggestions of idea's are welcome.

推荐答案

如果你可以与Gmail同步，你可以在导入联系人gmail.com（如CSV），再同步到手机上。

If you can sync with gmail, you could import contacts in gmail.com (as CSV) and sync them to the phone.

或者只是看到这样类似的问题：<一href=\"http://stackoverflow.com/questions/5596354/insertion-of-thousands-of-contact-entries-using-applybatch-is-slow\">Insertion数以千计的使用applyBatch联系人条目缓慢

Or just see this similar question: Insertion of thousands of contact entries using applyBatch is slow

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