如何在同一模型的架构方法中创建模型实例? [英] How I can create a model instance in the same model's schema method?

问题描述

主题.我想在它的静态方法中初始化模型的新实例:

Subject. I want init a new instance of model in it static method:

var Schema = new mongoose.Schema({...});

//...

Schema.statics.createInstance = function (name, pass) {
    var newPerson = new Person; // <--- or 'this', or 'Schema'?
    newPerson.name = name;
    newPerson.pass = pass;
    newPerson.save();
    return newPerson;
}

// ...

module.exports = db.model("Person", Schema);

我该怎么做?

推荐答案

您在正确的轨道上； this是架构在schema.statics方法中注册的模型，因此您的代码应更改为:

You were on the right track; this is the Model the schema is registered as within a schema.statics method, so your code should change to:

Schema.statics.createInstance = function (name, pass) {
    var newPerson = new this();
    newPerson.name = name;
    newPerson.pass = pass;
    newPerson.save();
    return newPerson;
}

列昂尼德(Leonid)关于处理save回调是正确的，即使只是记录错误也是如此.

And Leonid is right about handling the save callback, even if it's only to log errors.

这篇关于如何在同一模型的架构方法中创建模型实例?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！