如何在 Sequelize 模型中添加实例方法 [英] How to add an instance method in Sequelize model

问题描述

我想用 postgres 为 Sequelize User 模型添加一个实例方法.User 模型定义如下:

I would like to add an instance method to Sequelize User model with postgres. User model is defined as below:

const Sql = require('sequelize');
const db = require("../startup/db");

const User = db.define('user', {
    id: {type: Sql.INTEGER,
         primaryKey:true,
         min: 1},
    name: {type: Sql.STRING,
           allowNull: false,
           min: 2,
           max: 50
        },
    email: {type: Sql.STRING,
            isEmail: true},       
    encrypted_password: {type: Sql.STRING,
                         min: 8},
    createdAt: Sql.DATE,
    updatedAt: Sql.DATE
});

我在 User 模型中寻找类似的东西:

I am looking for something like this in model User:

User.instanceMethods.create(someMethod => function() {
   //method code here
   });

实例方法可以这样访问:

The instance method can be access like this:

let user = new User();
user.someMethod();

Sequelize中有模型的Instance，但实例方法没有.在 Sequelize 模型中添加实例方法的正确方法是什么?

There is Instance for model in Sequelize but it was not for the instance method. What is the right way to add instance method in Sequelize model?

推荐答案

这是问题的答案.请参阅 Mariano 的回复.

Here is the answer for the question. See reply by Mariano.

无法访问 Sequelize 实例方法

这里有更多阅读:https://codewithhugo.com/using-es6-classes-for-sequelize-4-models/

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