如何更新Django FileField实例的文件名? [英] How to update the filename of a Django's FileField instance?
问题描述
这是一个简单的Django模型:
Here a simple django model:
class SomeModel(models.Model):
title = models.CharField(max_length=100)
video = models.FileField(upload_to='video')
我想保存任何实例,以使video
的文件名成为title
的有效文件名.
I would like to save any instance so that the video
's file name would be a valid file name of the title
.
例如,在管理界面中,我加载了一个标题为"Lorem ipsum"和名为"video.avi"的视频的新实例.服务器上文件的副本应为"Lorem Ipsum.avi"(或"Lorem_Ipsum.avi").
For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi").
谢谢:)
推荐答案
If it just happens during save, as per the docs, you can pass a function to upload_to that will get called with the instance and the original filename and needs to return a string to be used as the filename. Maybe something like:
from django.template.defaultfilters import slugify
class SomeModel(models.Model):
title = models.CharField(max_length=100)
def video_filename(instance, filename):
fname, dot, extension = filename.rpartition('.')
slug = slugify(instance.title)
return '%s.%s' % (slug, extension)
video = models.FileField(upload_to=video_filename)
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