使用FileField在Django中保存原始文件名 [英] Saving Original File Name in Django with FileField
本文介绍了使用FileField在Django中保存原始文件名的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
self.original_filename = filename
extension = filename.rsplit('。',1)[1]
newfilename = uuid.uuid4().__ str __()+'。'+ extension
return self.directory()+ newfilename
class FileUpload(models.Model):
original_filename = models.CharField(max_length = 128)
fileobj = models.FileField(upload_to = generate_uuid_file_name)
在上传时,
{errors:{original_filename:[此字段为必填项。 },success:false}
添加blank = True,null = True FileUpload.original_filename允许上传成功,但不保存原始文件名。在django 1.5。根据这篇文章: Django:如何在FileField中保存原始文件名?这应该工作。任何帮助非常感谢。
解决方案
在视图中执行(null = True,blank = True再次成为模型的一部分):
file_object = UploadFileForm.save(commit = False)
file_object.original_filename = request.FILES ['file']。name
file_object.save()
请注意,您需要根据您的上下文等
def generate_uuid_file_name(self, filename):
self.original_filename = filename
extension = filename.rsplit('.', 1)[1]
newfilename = uuid.uuid4().__str__() + '.' + extension
return self.directory() + newfilename
class FileUpload(models.Model):
original_filename = models.CharField(max_length=128)
fileobj = models.FileField(upload_to=generate_uuid_file_name)
On upload,
{"errors": {"original_filename": ["This field is required."]}, "success": false}
Adding blank=True, null=True to the FileUpload.original_filename allows the upload to succeed but does not save the original file name. On django 1.5. According to this post: Django: How to save original filename in FileField? This should work. Any help much appreciated.
解决方案
Do that in the view (after null=True, blank=True are again part of your model):
file_object = UploadFileForm.save(commit=False)
file_object.original_filename = request.FILES['file'].name
file_object.save()
Mind that you will need to change the above code accordingly with your context etc
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