正则表达式匹配这个还是那个? [英] Regex match this OR that?

问题描述

正则表达式是什么?

匹配字符串

• 否(以.php结尾或以.html结尾或包含/)

• NOT ( ends in .php OR ends in .html OR contains / )

谢谢！

我需要NOT部分，因为该表达式将在Apache mod重写中使用，因为我无法更改mod_rewrite的逻辑来避免NOT.

I need the NOT part because the expression is to be used on an Apache mod rewrite, since I can't change the logic of mod_rewrite to avoid the NOT.

我最初的努力是([^/]+)(\.html)$(^\.php)$-这是非常错误的

My initial effort was ([^/]+)(\.html)$(^\.php)$ - which is monstrously wrong

推荐答案

Apache mod_rewrite 确实支持否定/mod/mod_rewrite.html"rel =" noreferrer>此文档.

Apache mod_rewrite does support negation, according to this document.

在mod_rewrite中，NOT字符 ('！')也可能 模式前缀.这使您能够 否定模式可以说 实例:``如果当前URL确实存在 不符合此模式''.这可以是 用于特殊情况下 更容易匹配否定词 模式，或作为最后的默认规则.

In mod_rewrite, the NOT character ('!') is also available as a possible pattern prefix. This enables you to negate a pattern; to say, for instance: ``if the current URL does NOT match this pattern''. This can be used for exceptional cases, where it is easier to match the negative pattern, or as a last default rule.

因此，您应该可以执行以下操作:

So you should be able to do something like:

!^(.*?/.*|.*?\.(?:php|html)$)$

这应该与不包含/并且以.php或.html结尾的任何内容匹配

And that should match anything which does not contain / and does not end in .php or .html

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