正则表达式匹配EOF [英] regex to match EOF

问题描述

我有一些看起来像这样的数据

约翰、戴夫、克里斯瑞克，山姆，鲍勃乔、米尔特、保罗

我正在使用这个正则表达式来匹配名称

/(\w.+?)(\r\n|\n|,)/

大部分情况下有效，但文件在最后一个单词之后突然结束，这意味着最后一个值不以 \r\n、\n 或 , 以EOF结尾.有没有办法在正则表达式中匹配 EOF，这样我就可以把它放在第二个分组中?

解决方案

这个问题的答案是 \Z 我花了一些时间才弄明白，但现在可以了.请注意，相反，\A 匹配整个字符串的开头(而不是 ^ 和 $ 匹配一行的开头).

I have some data that look like this

john, dave, chris
rick, sam, bob
joe, milt, paul

I'm using this regex to match the names

/(\w.+?)(\r\n|\n|,)/

which works for the most part but the file ends abruptly after the last word meaning the last value doesn't end in \r\n, \n or , it ends with EOF. Is there a way to match EOF in regex so I can put it right in that second grouping?

解决方案

The answer to this question is \Z took me awhile to figure it out, but it works now. Note that conversely, \A matches beginning of the whole string (as opposed to ^ and $ matching the beginning of one line).

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