正则表达式匹配句子 [英] Regular expression match a sentence
问题描述
如何匹配Hello world或Hello World形式的句子。句子可能包含 - / digit 0-9。任何信息对我都非常有帮助。谢谢。
How can I match a sentence of the form "Hello world" or "Hello World". The sentence may contain "- / digit 0-9". Any information will be very helpful to me. Thank you.
推荐答案
这个会做得很好。我对句子的定义:句子以非空格开头,以句号,感叹号或问号(或字符串结尾)结束。在结束标点符号后可能会有结束语。
This one will do a pretty good job. My definition of a sentence: A sentence begins with a non-whitespace and ends with a period, exclamation point or a question mark (or end of string). There may be a closing quote following the ending punctuation.
[^。!?\ ts] [^。!?] *(? [!?](?![ '] \s | $)[^。!?] *)* [。!?] ['](= \s | $)<? / code>
[^.!?\s][^.!?]*(?:[.!?](?!['"]?\s|$)[^.!?]*)*[.!?]?['"]?(?=\s|$)
import java.util.regex.*;
public class TEST {
public static void main(String[] args) {
String subjectString =
"This is a sentence. " +
"So is \"this\"! And is \"this?\" " +
"This is 'stackoverflow.com!' " +
"Hello World";
String[] sentences = null;
Pattern re = Pattern.compile(
"# Match a sentence ending in punctuation or EOS.\n" +
"[^.!?\\s] # First char is non-punct, non-ws\n" +
"[^.!?]* # Greedily consume up to punctuation.\n" +
"(?: # Group for unrolling the loop.\n" +
" [.!?] # (special) inner punctuation ok if\n" +
" (?!['\"]?\\s|$) # not followed by ws or EOS.\n" +
" [^.!?]* # Greedily consume up to punctuation.\n" +
")* # Zero or more (special normal*)\n" +
"[.!?]? # Optional ending punctuation.\n" +
"['\"]? # Optional closing quote.\n" +
"(?=\\s|$)",
Pattern.MULTILINE | Pattern.COMMENTS);
Matcher reMatcher = re.matcher(subjectString);
while (reMatcher.find()) {
System.out.println(reMatcher.group());
}
}
}
这是输出:
这是一个句子。
所以这个 !
并且是这个?
这是' stackoverflow.com!'
Hello World
匹配所有这些都正确(最后一句话没有结束标点符号),结果似乎并不那么容易!
Matching all of these correctly (with the last sentence having no ending punctuation), turns out to be not so easy as it seems!
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