如何在mod_rewrite中不匹配单词 [英] How to NOT match a word in mod_rewrite

问题描述

请帮助，我快疯了！

RewriteRule ^([a-z0-9_-]+)?/?search/?$ search.php?id=$1&%{QUERY_STRING} [NC,L]

这是我当前的代码.有时人们会访问mysite.com/search，而其他时候他们会访问mysite.com/boris/search，而我检测到用户的空($ _GET ['id'])支票.

This is my current code. Sometimes people will visit mysite.com/search, other times they will visit mysite.com/boris/search and I detect a user with an empty($_GET['id']) check.

但是我正在创建另一个搜索，该搜索指向mysite.com/products/search，该搜索导致了product_search.php

However I am creating another search, mysite.com/products/search which leads to products_search.php

我需要我的原始RewriteRule来匹配除产品"一词外的任何用户.

I need my original RewriteRule to match any user EXCEPT the word 'products'.

我尝试了很多组合.

RewriteRule ^(!products&[a-z0-9_-]+)?/?search/?$ search.php?id=$1&%{QUERY_STRING} [NC,L]

我对regex/mod_rewrite不太满意，但是上面的东西应该可以工作吗?我只需要一个AND运算符就可以清楚地知道&不起作用，但我找不到一个！

I'm not very good with regex/mod_rewrite but I something like the above should work? I just need an AND operator as clearly & doesn't work, but I can't find one!

非常感谢.

推荐答案

您有两个选择:要么使用RewriteCond来限制已经匹配的字符串:

You have two options: Either use a RewriteCond to restrict the already matched string:

RewriteCond $1 !=products
RewriteRule ^([a-z0-9_-]+)?/?search/?$ search.php?id=$1&%{QUERY_STRING} [NC,L]

或者从Apache 2开始，您还可以使用否定的前瞻断言:

Or since Apache 2, you can also use a negated look-ahead assertion:

RewriteRule ^(?!products/)([a-z0-9_-]+)?/?search/?$ search.php?id=$1&%{QUERY_STRING} [NC,L]

除此之外，您还可以使用 QSA 标志，而不是手动附加 QUERY_STRING .并请注意，您当前的模式还将允许/foobarsearch/之类的内容，因此它没有分隔的/.

Besides that, you can also use the QSA flag instead of appending QUERY_STRING manually. And note that your current pattern will also allow something like /foobarsearch/, so it doesn’t have the separating /.

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