Apache在URL中重写字符串-障碍是“?"在查询中 [英] Apache rewrite string in URL - obstacle is "?" in query

问题描述

想要从给定的用户前缀("u-")重写URL，

Want to rewrite an URL with a given user-prefix ("u-") from

https://example.com/access/check?user=u-abc&pass=123

不带前缀的URL:

https://example.com/access/check?user=abc&pass=123

我尝试了一些规则，例如

I tried several rules, e.g

RewriteBase /
RewriteRule ^access/check?user=u-(.*)$ check?user=$1

我坚持使用?"

如果重写必须适用于略微相同的内容，但是没有?"，则确实有效:

IF the rewrite had to apply to slightly the same, but without the "?", it indeed works:

https://example.com/access/checkuser=u-abc&pass=123

RewriteRule ^access/checkuser=u-(.*)$ checkuser=$1

并提供预期的结果(不带用户前缀"u-")

and provides the expected outcome (without the user-prefix "u-")

checkuser=abc&pass=123

我试图匹配?"和[?]或\ x3F，并按照 mod_rewrite.org ，但仍然没有成功.

I tried to match the "?" with [?] or \x3F, and applied the QSA flag as described on mod_rewrite.org , but still not succeeded.

推荐答案

查询字符串不是

The query string is not part of the RewriteRule pattern

匹配什么?

• ...
• 如果要与主机名，端口或查询字符串匹配，请分别使用RewriteCond和％{HTTP_HOST}，％{SERVER_PORT}或％{QUERY_STRING}变量.

因此，在您的情况下，您必须检查QUERY_STRING并使用替换%1代替$1

So in your case, you must check against QUERY_STRING and use the replacement %1 instead of $1

RewriteCond %{QUERY_STRING} user=u-(.*)
RewriteRule ^access/check$ /access/check?user=%1 [L]

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