PHP数组以模为单位的第二个值 [英] Php array modulo every second value

问题描述

我有一个问题.我有这个字母数组. 而且每个偶数字母都必须是！$字母，因此需要回显！b，！d，！f

I have a question. I have this array of the alphabet. And every even letter needs to be !$letter, so it needs to echo out !b, !d, !f

我不确定该怎么做.有人告诉我为此使用模数％.

I'm unsure how to do this. I've been told to use the modulo, % for this.

但是在Internet上阅读了很多有关它的信息后，对我来说还不清楚.

But reading a lot about it on the internet and things haven't gotten any clearer for me.

我感谢任何可以在此问题上为我提供帮助的人！ 预先感谢！

I appreciate anyone that can help me on this matter! Thanks in advance!

推荐答案

foreach ($alphabet as $i => $letter) {
    echo (($i % 2) == 1 ? '!' : '') . $letter;
}

$i是字母在数组中的位置；由于数组索引从0开始，所以偶数字母将具有奇数索引.

$i is the position of the letter in the array; since array indexes start from 0, even letters will have odd indexes.

$i % 2为0，当其为奇数时，1.这是小学数学，应该是编程生涯的先决条件.

$i % 2 is 0 when $i is even, 1 when it's odd. This is grade school arithmetic, which should be a prerequisite for a programming career.

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