按第二个值对二维数组排序 [英] Sorting a two-dimensional array by second value

问题描述

好吧，说我有一个像[[z，1]，[d，3]，[e，2]]这样的数组，我该如何通过每个组成数组的第二个元素对这个数组进行排序?这样我的数组如下所示? [[z，1]，[e，2]，[d，3]]?

Ok, say I have an array like so [[z,1], [d,3], [e,2]], how can I sort this array by the second element of each constituent array? So that my array would look like the following? [[z,1], [e,2], [d,3]]?

推荐答案

arr = [[:z,1], [:d,3], [:e,2]]
arr.sort {|a,b| a[1] <=> b[1]}
# => [[:z, 1], [:e, 2], [:d, 3]]

或者如用户@Phrogz所指出的，如果内部数组每个元素都有正好两个元素:

Or as user @Phrogz points out, if the inner arrays have exactly two elements each:

arr.sort_by{|x,y|y} # => [[:z, 1], [:e, 2], [:d, 3]]
arr.sort_by(&:last) # => [[:z, 1], [:e, 2], [:d, 3]]

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