根据子数组的第二个元素对多维数组进行排序 [英] Sort multidimensional array based on 2nd element of the subarray

问题描述

我有一个这样的数组:

[['G', 10], ['A', 22], ['S', 1], ['P', 14], ['V', 13], ['T', 7], ['C', 0], ['I', 219]]

我想按降序根据第二个元素对其进行排序.理想的输出是:

[['I', 219], ['A', 22], ['P', 14], ... ]

解决方案

list.sort, sorted 接受可选的 key 参数.key 函数用于生成比较键.

<预><代码>>>>排序(lst，key=lambda x:x[1]，reverse=True)[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]>>>排序(lst，键= lambda x:-x [1])[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]>>>进口经营者>>>排序(lst，key=operator.itemgetter(1)，reverse=True)[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]

I have an array like this:

[['G', 10], ['A', 22], ['S', 1], ['P', 14], ['V', 13], ['T', 7], ['C', 0], ['I', 219]]

I'd like to sort it based on the 2nd element in descending order. An ideal output would be:

[['I', 219], ['A', 22], ['P', 14], ... ]

解决方案

list.sort, sorted accept optional key parameter. key function is used to generate comparison key.

>>> sorted(lst, key=lambda x: x[1], reverse=True)
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]

>>> sorted(lst, key=lambda x: -x[1])
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]

>>> import operator
>>> sorted(lst, key=operator.itemgetter(1), reverse=True)
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]

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