mongodb concat int和字符串 [英] Mongodb concat int and string

问题描述

我正在尝试为集合中所有文件的FileName和FileSize投射50 mb或更大的文件，但我无法连接FileSize类型，因为它具有Int类型

I'm trying to project FileName and FileSize for all my files in my collection with a size of 50 mb and greater, but I cannot concat a the type FileSize as it has a type of Int

我希望投影成为

{
"result" : [ 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b6308"),
        "FileName" : "1234567890.xml",
        "FileSize" : "11.06 MB"
    }, 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b630f"),
        "FileName" : "2468101214.xml",
        "FileSize" : "320.48 MB"
    }, 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b631f"),
        "FileName" : "3691215180.xml",
        "FileSize" : "12.95 MB"
    }
}

但到目前为止，我只能返回以下内容

But so far I can Only return the following

{
"result" : [ 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b6308"),
        "FileName" : "1234567890.xml",
        "FileSize" : 11.0610504150390630
    }, 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b630f"),
        "FileName" : "2468101214.xml",
        "FileSize" : 320.4827098846435500
    }, 
    {
        "_id" : ObjectId("5652c399a21dad0bb01b631f"),
        "FileName" : "3691215180.xml",
        "FileSize" : 12.9519605636596680
    }
}

我的查询:

    db.MyCollection.aggregate(

  // Pipeline
  [
    // Stage 1
    {
      $match: {
      FileSize: {$gte: 5000000}
      }
    },
    // Stage 2
    {
      $project: {
        FileName: 1,
        FileSize: {$divide: ["$FileSize", 1048576]}
      }
    },
    // Stage 3
    {
        $project:{
            FileName:1,
            FileSize:{$concat:["$FileSize", "MB"]}
        }
     }

如何合并FileSize和"MB"字段?

How do I concat the FileSize and "MB" field?

推荐答案

这里的诀窍是使用 $substr 转换为字符串，还有一些额外的功能来处理小数点精度:

The trick here is to use $substr to do the conversion to a string, and a few little extras to handle the decimal point precision:

    { "$project": {
        "FileName": 1,
        "FileSize": {
            "$concat": [
                { "$substr": [
                    { "$subtract": [ "$FileSize", { "$mod": [ "$FileSize", 1 ] }]},
                    0,
                    -1
                ]},
                { "$substr": [ { "$mod": [ "$FileSize", 1 ] }, 1, 3] },
                " MB",
            ]
        }
    }}

或者更好的是，借助

Or better yet, combine into a single $project, either with the help of $let in versions later than MongoDB 2.6, or in long for if needed. A single pipeline stage is more efficient than two:

    { "$project": {
        "FileName": 1,
        "FileSize": {
            "$let": {
                "vars": {
                    "FileSize": { "$divide": [ "$FileSize", 1048576 ] }
                },
                "in":{
                    "$concat": [
                        { "$substr": [
                            { "$subtract": [ "$$FileSize", { "$mod": [ "$$FileSize", 1 ] }]},
                            0,
                            -1
                        ]},
                        { "$substr": [ { "$mod": [ "$$FileSize", 1 ] }, 1, 3] },
                        " MB",
                    ]
                }
            }
        }
    }}

只要您将数字分解为小数点(通过 $mod )，您可以向字符串的其余部分抛出"length"参数，以处理任意长度的数字.在将余数"与使用$mod分开的情况下，字符串的长度始终为小数点后两位是三"，当然要从第二个位置开始，以跳过前导0.

So as long as you break up the number at the decimal point ( via $mod ) you can throw a "length" argument to the rest of the string to deal with numbers of arbitary length. With the "remainder" separated from the use of $mod the length of the string to two decimal places is always "three", starting of course from the second position in order to skip the leading 0.

完全返回您的要求:

{
        "_id" : ObjectId("5652c399a21dad0bb01b6308"),
        "FileName" : "1234567890.xml",
        "FileSize" : "11.06 MB"
}
{
        "_id" : ObjectId("5652c399a21dad0bb01b630f"),
        "FileName" : "2468101214.xml",
        "FileSize" : "320.48 MB"
}
{
        "_id" : ObjectId("5652c399a21dad0bb01b631f"),
        "FileName" : "3691215180.xml",
        "FileSize" : "12.95 MB"
}

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